Voltage = Current x Resistance The Ammeter reads Current, so Current = Voltage divided by Resistance. It would be better if the Mr Tyler elaborates , what actually he means by "calculating Ammeter readings" Ammeters directly read the current in the circuit.The ammeter would have the same reading if located between points d and e or between points f and a as it does in the position shown. Figure 21.32 (a) An ammeter normally has such a small resistance that the total series resistance in the branch being measured is not appreciably increased.Given circuit is equivalent to the Wheatstone bridge (ABCD in figure). Since bridge is balanced no current will flow in branch CD, hence equivalent resistance between A and B is R1 =RAC +RCB 1 +RAD +RDB 1 +RAe +REB 1. The current through the circuit (read by the ammeter) is: I=RV.Sign in to Writing (Essays). Science. Physics Physics for Scientists and Engineers: Foundations and Connections The reading on the ammeter in Figure 1 Getting Started 2 One Dimensional Motion 3 Vectors 4 Two-and-three Dimensional Motion 5 Newton's Laws Of Motion 6 Applications Of Newton's...Homework Statement The ammeter reads 5.0A. Find I1, I2, and ε Homework Equations ΔV=IR The Attempt at a Solution I've never dealt with ammeters before... I've gone through many different methods and have been unsuccessful in all, and am really just trying to figure out where to even start.
21.4 DC Voltmeters and Ammeters - College Physics | OpenStax
Transcribed Image Text from this Question. The ammeter in the figure reads 3.0 A. (Figure 1). Find I1.Find I2.Find E.The ammeter shown in the. figure reads 2.00 A. Find I1, I2, and. 29. For the circuit shown in Figure P28.29, calculate (a) the current in the 2.00-Ω resistor and (b) the potential difference between points a and b.An ammeter placed in series with an electric radiator reads 0.5 amps and a voltmeter placed across it reads 230 volts. asked Dec 18, 2018 in Class X Science by An electric circuit consisting of a 0.5 m long nichrome write XY an ammeter a voltmeter four cells of 1.5 V each and a plug key was set up.The ammeter in FIGURE P32.… We are giving this circuit diagram, and then the media reading is to MPs. We need to determine I one i two and the m e. So to do this, first we consider this look, um, the one.
The ammeter in the given figure will read | Toppr Ask
Neglect the resistances of the ammeter. Answer. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.Problem 1 is producing these symptoms: the ammeter reads 0 A, ΔV1 reads 0 V, and ΔV2 reads 45 V. What has happened? Suppose that a wire is added to connect points A and B. Answer the following questions, and explain your reasoning. Figure 10 a. What is the current through the wire? b...(See (Figure), where the ammeter is represented by the symbol A.) The ammeter would have the same reading if located between points d and e or between points f and a as it Voltmeters measure voltage, and ammeters measure current. A voltmeter is placed in parallel with the voltage source to...We're in the know. This site is using cookies under cookie policy. You can specify conditions of storing and accessing cookies in your browser.Reset 1. Enzyme- acetylcholine esterase is found in the synaptic cleft, which destroys acetylcholine about as fast at is made, so ACH is present in synaptic cleft for only a short amount of time 2 Enter your email below to unlock your verified solution to: The ammeter in Figure P23.24 reads 3.0 A. Find .
Concepts and reason why
The concept used here's Kirchhoff's current legislation and Kirchhoff's voltage regulation. Firstly, apply Kirchhoff's current legislation to the left loop and Kirchhoff's voltage law to the proper loop and use the equation obtained from the loop to calculate the current \(I_2\). In the 2d part, calculate the value of \(\varepsilon\) by means of the usage of the price of present calculated in the earlier part.
Fundamentals
Kirchhoff's current regulation:
At any junction in circuit, the algebraic sum of currents shall be zero. Kirchhoff's voltage legislation:
In any closed loop of circuit, the algebraic sum of voltages might be zero.
The following figure presentations the given circuit diagram.
In this circuit diagram, level A and B is proven, at level A each currents are coming and they'll undergo A to B.
a) The Kirchhoff's current law is used at junction \(\mathrmA\), it's written as, \(I_1+I_2=I_A B \ldots \ldots\) (1)
The current between \(\mathrmA\) and \(\mathrmB\), it method the current \(I_A B\) shall be equal to the reading of connected ammeter, which is
\(3 \mathrm~A\). Therefore, it is written as, \(I_A B=3 \mathrm~A\)
The voltage difference between \(A\) and \(B\) is written as, \(V_A B=I_A B R_A B\)
Substitute \(3 \mathrm~A\) for \(I_A B\) and \(2 \Omega\) for \(R_A B\) in above expression.
$$ \beginaligned V_A B &=(3 \mathrm~A)(2 \Omega) \ &=6 \mathrm~V \finishaligned $$
Apply the Kirchhoff's voltage law in loop 1 , it is written as, \(9 \mathrm~V-3 I_1=V_A B\)
Substitute the value \(6 \mathrm~V\) for \(V_A B\) in above expression.
$$ \beginarrayc 9 \mathrm~V-3 I_1=6 \mathrm~V \ 3 I_1=3 \mathrm~V \ I_1=1 \mathrm~A \endarray $$
Substitute the value \(3 \mathrm~A\) for \(I_A B\) and \(1 \mathrm~A\) for \(I_1\) in expression (1)
\(1 \mathrm~A+I_2=3 \mathrm~A\)
$$ I_2=2 \mathrm~A $$
Part a The price of \(I_2\) is \(2 \mathrm~A\).
Apply the Kirchhoff's current law to seek out the relation between currents, apply the Kirchhoff's voltage law and calculate \(I_1\) and with the assist of \(I_1\), calculate the worth \(I_2\).
(b) Apply the Kirchhoff's voltage law in loop 2 , it's written as, \(\varepsilon-4.Five I_2=V_A B\)
Substitute the value \(6 \mathrm~V\) for \(V_A B\) and \(2 \mathrm~A\) for \(I_2\) in above expression.
$$ \startarrayc \varepsilon-4.5(2 \mathrm~A)=6 \mathrm~V \ \varepsilon=15 \mathrm~V \finisharray $$
Part b The worth of \(\varepsilon\) is \(15 \mathrm~V\).
Apply the Kirchhoff's voltage regulation and calculate \(I_1\) and with the lend a hand of \(I_1\), calculate the worth \(I_2\). Apply the Kirchhoff's voltage regulation in loop 2 and calculate the \(\varepsilon\).
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